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how to post image data through javascript

user2392 Published in April 24, 2018, 8:36 am

I have a html form which sends POST data to my PHP script

It also uses AJAX to provide a preview as they complete the form

However the form uses onsubmit=""

The issue i have is one of the html inputs is an image.

the form is as below to give you an idea:

<form method="post" action="scripts/test.php" enctype="multipart/form-data">
<input type="hidden" name="size" id="size" value="small" />
<input type="hidden" name="type" id="type" value="1" />
<input type="hidden" name="pos" id="pos" value="front" />
<input type="hidden" name="number" id="number" value="none" />
<input type="hidden" name="name" id="name" value="none" />
<label>Choose Your First Shirt Colour</label><br /> <input class="color" value="ff3300" id="colour1" name="colour1" onchange="change()">
<br /><br />
<label>Choose Your Second Shirt Colour</label><br />
<input class="color" value="FFFFFF" id="colour2" name="colour2" onchange="change()">
<br /><br /><label>Add Your Logo: <br />
<span style="font-size:11px;color:#FF0000;">(if you are having trouble adding your logo please contact us on 0845 6018370)</span></label>
<br />
<input type="file" name="logo" id="logo" onchange="change()"/><br /><br />
<label>Add Your Text:</label><br />
<textarea name="text" cols="30" id="text" rows="5" onchange="change()"></textarea><br />
<label><span style="color:#000000;">Quantity: </span></label>
<input type="text" id="quantity" name="quantity" value="1" style="width:40px;height:20px;"/><br /><br />
<input type="button" name="preview" value="Preview" onclick="MyPreview()"/><br />
<input type="submit" name="submit" value="Submit" />

I am using

var logo =document.getElementById("logo").value;

for the image but when i am sending the logo value through to PHP it breaks the image as it isn't the correct post value required to be sent through to the PHP script as though you are submitting the form.

Does anyone know how to get the same post value for the logo html field simply by using onchange and javascript?

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