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Ignoring Duplicate Records SQL

user7570 Published in September 19, 2018, 6:44 pm

In need of some help :)

So I have a table of records with the following columns:

Key (PK, FK, int) DT (smalldatetime) Value (real)

The DT is a datetime for every half hour of the day with an associated value


Key       DT                       VALUE
1000      2010-01-01 08:00:00      80
1000      2010-01-01 08:30:00      75
1000      2010-01-01 09:00:00      100

I have a Query that finds the max value every 24 hour period and its associated time however, on one day the max value occurs twice and hence duplicates the date which is causing processing issues. I have tried using rownumber() which works but I can't use a calculated column in my where clause? Currently I have:

SELECT       cast(T1.DT as date) as 'Date',Cast(T1.DT as time(0)) as 'HH', ROW_NUMBER() over (PARTITION BY  cast(DT as date) ORDER BY DT) AS 'RowNumber'
FROM        TABLE_1 AS T1
                SELECT CAST([DT] as date) as 'DATE'
                ,       MAX([VALUE]) as 'MAX_HH'
                FROM    TABLE_1
                WHERE   DT > '6-nov-2016' and [KEY] = '1000'
                GROUP BY CAST([DT] as date)
            ) AS MAX_DT
        ON  MAX_DT.[DATE] = CAST(T1.[DT] as date)
WHERE       DT > '6-nov-2016' and [KEY] = '1000'

This results in

Key       DT               VALUE       HH
1000      2010-01-01       80          07:00:00
1000      2010-02-01       100         17:30:00
1000      2010-02-01       100         18:00:00

I need to remove the duplicate date (I Have no preference which HH it takes)

I think I've explained that terribly, let me know if it makes no sense and i'll try and re write

Any ideas?

share|improve this question
  • With row_number() I suppose it's either oracle either sqlserver – Daniel E. Nov 13 '17 at 14:37
  • SQL SERVER - My Apologies – squib1996 Nov 13 '17 at 14:41

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