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# Error using timeout command - invalid time interval

Hamid Reza
1#
Hamid Reza Published in 2018-02-12 05:53:16Z
 I want to kill a command after waiting for result for 2 seconds. If the command didn't come up with a result (took too long), the command should stop. I have gone through the documents and tested the following command: timeout --kill-after=2 ls /mnt/ftp/; echo $?;  Or timeout -k 2 ls /mnt/ftp/; echo$?;  However, I am getting this error: timeout: invalid time interval ‘ls’  Note: The command below stops after timeout period by doesn't kill the process: timeout 2 ls /mnt/ftp/; 
Inian
2#
 The documentation for timeout is tricky in a way. If you refer it carefully it says \$ timeout --help Usage: timeout [OPTION] DURATION COMMAND [ARG]... or: timeout [OPTION] Start COMMAND, and kill it if still running after DURATION.  Here the option -k itself takes a value followed by a value needed for DURATION also, so your command should two values back to back when using -k as below. The error is thrown because DURATION is a mandatory argument to be used. timeout --kill-after=2 2 ls /mnt/ftp/;  The first option --kill-after=2 is part of the OPTION flag to the command which takes value 2 and the DURATION itself takes a value 2 separately. timeout -k 2 2 ls /mnt/ftp/;