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JavaScript closure inside loops – simple practical example

nickf
1#
nickf Published in 2009-04-15 06:06:20Z

var funcs = [];
for (var i = 0; i < 3; i++) {      // let's create 3 functions
  funcs[i] = function() {          // and store them in funcs
    console.log("My value: " + i); // each should log its value.
  };
}
for (var j = 0; j < 3; j++) {
  funcs[j]();                      // and now let's run each one to see
}

It outputs this:

My value: 3
My value: 3
My value: 3

Whereas I'd like it to output:

My value: 0
My value: 1
My value: 2


The same problem occurs when the delay in running the function is caused by using event listeners:

var buttons = document.getElementsByTagName("button");
for (var i = 0; i < buttons.length; i++) {          // let's create 3 functions
  buttons[i].addEventListener("click", function() { // as event listeners
    console.log("My value: " + i);                  // each should log its value.
  });
}
<button>0</button><br>
<button>1</button><br>
<button>2</button>

What's the solution to this basic problem?

User
2#
User Reply to 2017-03-31 19:54:45Z

Well, the problem is that the variable i, within each of your anonymous functions, is bound to the same variable outside of the function.

What you want to do is bind the variable within each function to a separate, unchanging value outside of the function:

var funcs = [];

function createfunc(i) {
    return function() { console.log("My value: " + i); };
}

for (var i = 0; i < 3; i++) {
    funcs[i] = createfunc(i);
}

for (var j = 0; j < 3; j++) {
    funcs[j]();                        // and now let's run each one to see
}

Since there is no block scope in JavaScript - only function scope - by wrapping the function creation in a new function, you ensure that the value of "i" remains as you intended.


Update: with the relatively widespread availability of the Array.prototype.forEach function (in 2015), it's worth noting that in those situations involving iteration primarily over an array of values, .forEach() provides a clean, natural way to get a distinct closure for every iteration. That is, assuming you've got some sort of array containing values (DOM references, objects, whatever), and the problem arises of setting up callbacks specific to each element, you can do this:

var someArray = [ /* whatever */ ];
// ...
someArray.forEach(function(arrayElement) {
  // ... code code code for this one element
  someAsynchronousFunction(arrayElement, function() {
    arrayElement.doSomething();
  });
});

The idea is that each invocation of the callback function used with the .forEach loop will be its own closure. The parameter passed in to that handler is the array element specific to that particular step of the iteration. If it's used in an asynchronous callback, it won't collide with any of the other callbacks established at other steps of the iteration.

If you happen to be working in jQuery, the $.each() function gives you a similar capability.

Update 2: ECMAScript 6 (ES6), the newest version of JavaScript, is now starting to be implemented in many evergreen browsers and backend systems. There are also transpilers like Babel that will convert ES6 to ES5 to allow usage of new features on older systems.

ES6 introduces new let and const keywords that are scoped differently than var-based variables. For example, in a loop with a let-based index, each iteration through the loop will have a new value of i where each value is scoped inside the loop, so your code would work as you expect. There are many resources, but I'd recommend 2ality's block-scoping post as a great source of information.

for (let i = 0; i < 3; i++) {
    funcs[i] = function() {
        console.log("My value: " + i);
    };
}

Beware, though, that IE9-IE11 and Edge prior to Edge 14 support let but get the above wrong (they don't create a new i each time, so all the functions above would log 3 like they would if we used var). Edge 14 finally gets it right.

Community
3#
Community Reply to 2017-05-23 12:18:27Z

Try:

var funcs = [];

for (var i = 0; i < 3; i++) {
    funcs[i] = (function(index) {
        return function() {
            console.log("My value: " + index);
        };
    }(i));
}
for (var j = 0; j < 3; j++) {
    funcs[j]();
}

Edit (2014):

Personally I think @Aust's more recent answer about using .bind is the best way to do this kind of thing now. There's also lo-dash/underscore's _.partial when you don't need or want to mess with bind's thisArg.

Nae
4#
Nae Reply to 2017-12-26 20:27:18Z

The reason your original example did not work is that all the closures you created in the loop referenced the same frame. In effect, having 3 methods on one object with only a single i variable. They all printed out the same value.

eglasius
5#
eglasius Reply to 2009-04-15 06:31:15Z

What you need to understand is the scope of the variables in javascript is based on the function. This is an important difference than say c# where you have block scope, and just copying the variable to one inside the for will work.

Wrapping it in a function that evaluates returning the function like apphacker's answer will do the trick, as the variable now has the function scope.

There is also a let keyword instead of var, that would allow using the block scope rule. In that case defining a variable inside the for would do the trick. That said, the let keyword isn't a practical solution because of compatibility.

var funcs = {};
for (var i = 0; i < 3; i++) {
    let index = i;          //add this
    funcs[i] = function() {            
        console.log("My value: " + index); //change to the copy
    };
}
for (var j = 0; j < 3; j++) {
    funcs[j]();                        
}
Nae
6#
Nae Reply to 2017-12-26 11:07:51Z

Another way of saying it is that the i in your function is bound at the time of executing the function, not the time of creating the function.

When you create the closure, i is a reference to the variable defined in the outside scope, not a copy of it as it was when you created the closure. It will be evaluated at the time of execution.

Most of the other answers provide ways to work around by creating another variable that won't change the value for you.

Just thought I'd add an explanation for clarity. For a solution, personally, I'd go with Harto's since it is the most self-explanatory way of doing it from the answers here. Any of the code posted will work, but I'd opt for a closure factory over having to write a pile of comments to explain why I'm declaring a new variable(Freddy and 1800's) or have weird embedded closure syntax(apphacker).

Boann
7#
Boann Reply to 2012-08-07 08:45:35Z

Here's another variation on the technique, similar to Bjorn's (apphacker), which lets you assign the variable value inside the function rather than passing it as a parameter, which might be clearer sometimes:

for (var i = 0; i < 3; i++) {
    funcs[i] = (function() {
        var index = i;
        return function() {
            console.log("My value: " + index);
        }
    })();
}

Note that whatever technique you use, the index variable becomes a sort of static variable, bound to the returned copy of the inner function. I.e., changes to its value are preserved between calls. It can be very handy.

Lucas
8#
Lucas Reply to 2013-04-20 09:59:57Z

This describes the common mistake with using closures in JavaScript.

A function defines a new environment

Consider:

function makeCounter()
{
  var obj = {counter: 0};
  return {
    inc: function(){obj.counter ++;},
    get: function(){return obj.counter;}
  };
}

counter1 = makeCounter();
counter2 = makeCounter();

counter1.inc();

alert(counter1.get()); // returns 1
alert(counter2.get()); // returns 0

For each time makeCounter is invoked, {counter: 0} results in a new object being created. Also, a new copy of obj is created as well to reference the new object. Thus, counter1 and counter2 are independent of each other.

Closures in loops

Using a closure in a loop is tricky.

Consider:

var counters = [];

function makeCounters(num)
{
  for (var i = 0; i < num; i++)
  {
    var obj = {counter: 0};
    counters[i] = {
      inc: function(){obj.counter++;},
      get: function(){return obj.counter;}
    }; 
  }
}

makeCounters(2);

counters[0].inc();

alert(counters[0].get()); // returns 1
alert(counters[1].get()); // returns 1

Notice that counters[0] and counters[1] are not independent. In fact, they operate on the same obj!

This is because there is only one copy of obj shared across all iterations of the loop, perhaps for performance reasons. Even though {counter: 0} creates a new object in each iteration, the same copy of obj will just get updated with a reference to the newest object.

Solution is to use another helper function:

function makeHelper(obj)
{
  return {
    inc: function(){obj.counter++;},
    get: function(){return obj.counter;}
  }; 
}

function makeCounters(num)
{
  for (var i = 0; i < num; i++)
  {
    var obj = {counter: 0};
    counters[i] = makeHelper(obj);
  }
}

This works because local variables in the function scope directly, as well as function argument variables, are allocated new copies upon entry.

For a detailed discussion, please see JavaScript closure pitfalls and usage

Ben McCormick
9#
Ben McCormick Reply to 2017-07-27 16:53:24Z

With ES6 now widely supported, the best answer to this question has changed. ES6 provides the let and const keywords for this exact circumstance. Instead of messing around with closures, we can just use let to set a loop scope variable like this:

var funcs = [];
for (let i = 0; i < 3; i++) {          
    funcs[i] = function() {            
      console.log("My value: " + i); 
    };
}

val will then point to an object that is specific to that particular turn of the loop, and will return the correct value without the additional closure notation. This obviously significantly simplifies this problem.

const is similar to let with the additional restriction that the variable name can't be rebound to a new reference after initial assignment.

Browser support is now here for those targeting the latest versions of browsers. const/let are currently supported in the latest Firefox, Safari, Edge and Chrome. It also is supported in Node, and you can use it anywhere by taking advantage of build tools like Babel. You can see a working example here: http://jsfiddle.net/ben336/rbU4t/2/

Docs here:

  • const
  • let

Beware, though, that IE9-IE11 and Edge prior to Edge 14 support let but get the above wrong (they don't create a new i each time, so all the functions above would log 3 like they would if we used var). Edge 14 finally gets it right.

Kemal Dağ
10#
Kemal Dağ Reply to 2017-12-28 08:07:40Z

The most simple solution would be,

Instead of using:

var funcs = [];
for(var i =0; i<3; i++){
    funcs[i] = function(){
        alert(i);
    }
}

for(var j =0; j<3; j++){
    funcs[j]();
}

which alerts "2", for 3 times. This is because anonymous functions created in for loop, shares same closure, and in that closure, the value of i is the same. Use this to prevent shared closure:

var funcs = [];
for(var new_i =0; new_i<3; new_i++){
    (function(i){
        funcs[i] = function(){
            alert(i);
        }
    })(new_i);
}

for(var j =0; j<3; j++){
    funcs[j]();
}

The idea behind this is, encapsulating the entire body of the for loop with an IIFE (Immediately-Invoked Function Expression) and passing new_i as a parameter and capturing it as i. Since the anonymous function is executed immediately, the i value is different for each function defined inside the anonymous function.

This solution seems to fit any such problem since it will require minimal changes to the original code suffering from this issue. In fact, this is by design, it should not be an issue at all!

yilmazburk
11#
yilmazburk Reply to 2013-09-19 14:20:24Z

try this shorter one

  • no array

  • no extra for loop


for (var i = 0; i < 3; i++) {
    createfunc(i)();
}

function createfunc(i) {
    return function(){console.log("My value: " + i);};
}

http://jsfiddle.net/7P6EN/

Aust
12#
Aust Reply to 2015-06-29 16:15:03Z

Another way that hasn't been mentioned yet is the use of Function.prototype.bind

var funcs = {};
for (var i = 0; i < 3; i++) {
    funcs[i] = function(x) {
        console.log('My value: ' + x);
    }.bind(this, i);
}
for (var j = 0; j < 3; j++) {
    funcs[j]();
}

jsFiddle

UPDATE

As pointed out by @squint and @mekdev, you get better performance by creating the function outside the loop first and then binding the results within the loop.

function log(x) {
    console.log('My value: ' + x);
}

var funcs = [];

for (var i = 0; i < 3; i++) {
    funcs[i] = log.bind(this, i);
}

for (var j = 0; j < 3; j++) {
    funcs[j]();
}

jsFiddle

neurosnap
13#
neurosnap Reply to 2015-09-22 13:47:05Z

Using an Immediately-Invoked Function Expression, the simplest and most readable way to enclose an index variable:

for (var i = 0; i < 3; i++) {

    (function(index) {
        console.log('iterator: ' + index);
        //now you can also loop an ajax call here 
        //without losing track of the iterator value: $.ajax({});
    })(i);

}

This sends the iterator i into the anonymous function of which we define as index. This creates a closure, where the variable i gets saved for later use in any asynchronous functionality within the IIFE.

Travis J
14#
Travis J Reply to 2014-03-05 23:03:24Z

The main issue with the code shown by the OP is that i is never read until the second loop. To demonstrate, imagine seeing an error inside of the code

funcs[i] = function() {            // and store them in funcs
    throw new Error("test");
    console.log("My value: " + i); // each should log its value.
};

The error actually does not occur until funcs[someIndex] is executed (). Using this same logic, it should be apparent that the value of i is also not collected until this point either. Once the original loop finishes, i++ brings i to the value of 3 which results in the condition i < 3 failing and the loop ending. At this point, i is 3 and so when funcs[someIndex]() is used, and i is evaluated, it is 3 - every time.

To get past this, you must evaluate i as it is encountered. Note that this has already happened in the form of funcs[i] (where there are 3 unique indexes). There are several ways to capture this value. One is to pass it in as a parameter to a function which is shown in several ways already here.

Another option is to construct a function object which will be able to close over the variable. That can be accomplished thusly

jsFiddle Demo

funcs[i] = new function() {   
    var closedVariable = i;
    return function(){
        console.log("My value: " + closedVariable); 
    };
};
Daryl
15#
Daryl Reply to 2014-05-03 03:42:57Z

Here's a simple solution that uses forEach (works back to IE9):

var funcs = {};
[0,1,2].forEach(function(i) {          // let's create 3 functions
    funcs[i] = function() {            // and store them in funcs
        console.log("My value: " + i); // each should log its value.
    };
})
for (var j = 0; j < 3; j++) {
    funcs[j]();                        // and now let's run each one to see
}

Prints:

My value: 0
My value: 1
My value: 2
Community
16#
Community Reply to 2017-05-23 12:02:57Z

After reading through various solutions, I'd like to add that the reason those solutions work is to rely on the concept of scope chain. It's the way JavaScript resolve a variable during execution.

  • Each function definition forms a scope consisting of all the local variables declared by var and its arguments.
  • If we have inner function defined inside another (outer) function, this forms a chain, and will be used during execution
  • When a function gets executed, the runtime evaluates variables by searching the scope chain. If a variable can be found in a certain point of the chain it will stop searching and use it, otherwise it continues until the global scope reached which belongs to window.

In the initial code:

funcs = {};
for (var i = 0; i < 3; i++) {         
  funcs[i] = function inner() {        // function inner's scope contains nothing
    console.log("My value: " + i);    
  };
}
console.log(window.i)                  // test value 'i', print 3

When funcs gets executed, the scope chain will be function inner -> global. Since the variable i cannot be found in function inner (neither declared using var nor passed as arguments), it continues to search, until the value of i is eventually found in the global scope which is window.i.

By wrapping it in an outer function either explicitly define a helper function like harto did or use an anonymous function like Bjorn did:

funcs = {};
function outer(i) {              // function outer's scope contains 'i'
  return function inner() {      // function inner, closure created
   console.log("My value: " + i);
  };
}
for (var i = 0; i < 3; i++) {
  funcs[i] = outer(i);
}
console.log(window.i)          // print 3 still

When funcs gets executed, now the scope chain will be function inner -> function outer. This time i can be found in the outer function's scope which is executed 3 times in the for loop, each time has value i bound correctly. It won't use the value of window.i when inner executed.

More detail can be found here
It includes the common mistake in creating closure in the loop as what we have here, as well as why we need closure and the performance consideration.

Nae
17#
Nae Reply to 2017-12-26 19:51:50Z

I'm surprised no one yet has suggested using the forEach function to better avoid (re)using local variables. In fact, I'm not using for(var i ...) at all anymore for this reason.

[0,2,3].forEach(function(i){ console.log('My value:', i); });
// My value: 0
// My value: 2
// My value: 3

// edited to use forEach instead of map.

woojoo666
18#
woojoo666 Reply to 2017-07-06 19:46:03Z

Bit late to the party, but I was exploring this issue today and noticed that many of the answers don't completely address how Javascript treats scopes, which is essentially what this boils down to.

So as many others mentioned, the problem is that the inner function is referencing the same i variable. So why don't we just create a new local variable each iteration, and have the inner function reference that instead?

//overwrite console.log() so you can see the console output
console.log = function(msg) {document.body.innerHTML += '<p>' + msg + '</p>';};

var funcs = {};
for (var i = 0; i < 3; i++) {
    var ilocal = i; //create a new local variable
    funcs[i] = function() {
        console.log("My value: " + ilocal); //each should reference its own local variable
    };
}
for (var j = 0; j < 3; j++) {
    funcs[j]();
}

Just like before, where each inner function outputted the last value assigned to i, now each inner function just outputs the last value assigned to ilocal. But shouldn't each iteration have it's own ilocal?

Turns out, that's the issue. Each iteration is sharing the same scope, so every iteration after the first is just overwriting ilocal. From MDN:

Important: JavaScript does not have block scope. Variables introduced with a block are scoped to the containing function or script, and the effects of setting them persist beyond the block itself. In other words, block statements do not introduce a scope. Although "standalone" blocks are valid syntax, you do not want to use standalone blocks in JavaScript, because they don't do what you think they do, if you think they do anything like such blocks in C or Java.

Reiterated for emphasis:

JavaScript does not have block scope. Variables introduced with a block are scoped to the containing function or script

We can see this by checking ilocal before we declare it in each iteration:

//overwrite console.log() so you can see the console output
console.log = function(msg) {document.body.innerHTML += '<p>' + msg + '</p>';};

var funcs = {};
for (var i = 0; i < 3; i++) {
  console.log(ilocal);
  var ilocal = i;
}

This is exactly why this bug is so tricky. Even though you are redeclaring a variable, Javascript won't throw an error, and JSLint won't even throw a warning. This is also why the best way to solve this is to take advantage of closures, which is essentially the idea that in Javascript, inner functions have access to outer variables because inner scopes "enclose" outer scopes.

This also means that inner functions "hold onto" outer variables and keep them alive, even if the outer function returns. To utilize this, we create and call a wrapper function purely to make a new scope, declare ilocal in the new scope, and return an inner function that uses ilocal (more explanation below):

//overwrite console.log() so you can see the console output
console.log = function(msg) {document.body.innerHTML += '<p>' + msg + '</p>';};

var funcs = {};
for (var i = 0; i < 3; i++) {
    funcs[i] = (function() { //create a new scope using a wrapper function
        var ilocal = i; //capture i into a local var
        return function() { //return the inner function
            console.log("My value: " + ilocal);
        };
    })(); //remember to run the wrapper function
}
for (var j = 0; j < 3; j++) {
    funcs[j]();
}

Creating the inner function inside a wrapper function gives the inner function a private environment that only it can access, a "closure". Thus, every time we call the wrapper function we create a new inner function with it's own separate environment, ensuring that the ilocal variables don't collide and overwrite each other. A few minor optimizations gives the final answer that many other SO users gave:

//overwrite console.log() so you can see the console output
console.log = function(msg) {document.body.innerHTML += '<p>' + msg + '</p>';};

var funcs = {};
for (var i = 0; i < 3; i++) {
    funcs[i] = wrapper(i);
}
for (var j = 0; j < 3; j++) {
    funcs[j]();
}
//creates a separate environment for the inner function
function wrapper(ilocal) {
    return function() { //return the inner function
        console.log("My value: " + ilocal);
    };
}

Nae
19#
Nae Reply to 2017-12-27 00:10:53Z

This is a problem often encountered with asynchronous code, the variable i is mutable and at the time at which the function call is made the code using i will be executed and i will have mutated to its last value, thus meaning all functions created within the loop will create a closure and i will be equal to 3 (the upper bound + 1 of the for loop.

A workaround to this, is to create a function that will hold the value of i for each iteration and force a copy i (as it is a primitive, think of it as a snapshot if it helps you).

Rune FS
20#
Rune FS Reply to 2015-10-27 10:15:11Z

You could use a declarative module for lists of data such as query-js(*). In these situations I personally find a declarative approach less surprising

var funcs = Query.range(0,3).each(function(i){
     return  function() {
        console.log("My value: " + i);
    };
});

You could then use your second loop and get the expected result or you could do

funcs.iterate(function(f){ f(); });

(*) I'm the author of query-js and therefor biased towards using it, so don't take my words as a recommendation for said library only for the declarative approach :)

Ram
21#
Ram Reply to 2015-12-17 15:14:47Z

I prefer to use forEach function, which has its own closure with creating a pseudo range:

var funcs = [];

new Array(3).fill(0).forEach(function (_, i) { // creating a range
    funcs[i] = function() {            
        // now i is safely incapsulated 
        console.log("My value: " + i);
    };
});

for (var j = 0; j < 3; j++) {
    funcs[j](); // 0, 1, 2
}

That looks uglier than ranges in other languages, but IMHO less monstrous than other solutions.

pixel 67
22#
pixel 67 Reply to 2017-08-28 16:37:06Z

And yet another solution: instead of creating another loop, just bind the this to the return function.

var funcs = [];

function createFunc(i) {
  return function() {
    console.log('My value: ' + i); //log value of i.
  }.call(this);
}

for (var i = 1; i <= 5; i++) {  //5 functions
  funcs[i] = createFunc(i);     // call createFunc() i=5 times
}

By binding this, solves the problem as well.

YakovL
23#
YakovL Reply to 2017-12-26 22:46:45Z

First of all, understand what's wrong with this code:

var funcs = [];
for (var i = 0; i < 3; i++) {          // let's create 3 functions
    funcs[i] = function() {            // and store them in funcs
        console.log("My value: " + i); // each should log its value.
    };
}
for (var j = 0; j < 3; j++) {
    funcs[j]();                        // and now let's run each one to see
}

Here when the funcs[] array is being initialized, i is being incremented, the funcs array is initialized and the size of func array becomes 3, so i = 3,. Now when the funcs[j]() is called, it is again using the variable i, which has already been incremented to 3.

Now to solve this, we have many options. Below are two of them:

  1. We can initialize i with let or initialize a new variable index with let and make it equal to i. So when the call is being made, index will be used and its scope will end after initialization. And for calling, index will be initialized again:

    var funcs = [];
    for (var i = 0; i < 3; i++) {          
        let index = i;
        funcs[i] = function() {            
            console.log("My value: " + index); 
        };
    }
    for (var j = 0; j < 3; j++) {
        funcs[j]();                        
    }
    
  2. Other Option can be to introduce a tempFunc which returns the actual function:

    var funcs = [];
    function tempFunc(i){
        return function(){
            console.log("My value: " + i);
        };
    }
    for (var i = 0; i < 3; i++) {  
        funcs[i] = tempFunc(i);                                     
    }
    for (var j = 0; j < 3; j++) {
        funcs[j]();                        
    }
    
Nae
24#
Nae Reply to 2017-12-26 22:53:29Z

Your code doesn't work, because what it does is:

Create variable `funcs` and assign it an empty array;  
Loop from 0 up until it is less than 3 and assign it to variable `i`;
    Push to variable `funcs` next function:  
        // Only push (save), but don't execute
        **Write to console current value of variable `i`;**

// First loop has ended, i = 3;

Loop from 0 up until it is less than 3 and assign it to variable `j`;
    Call `j`-th function from variable `funcs`:  
        **Write to console current value of variable `i`;**  
        // Ask yourself NOW! What is the value of i?

Now the question is, what is the value of variable i when the function is called? Because the first loop is created with the condition of i < 3, it stops immediately when the condition is false, so it is i = 3.

You need to understand that, in time when your functions are created, none of their code is executed, it is only saved for later. And so when they are called later, the interpreter executes them and asks: "What is the current value of i?"

So, your goal is to first save the value of i to function and only after that save the function to funcs. This could be done for example this way:

var funcs = [];
for (var i = 0; i < 3; i++) {          // let's create 3 functions
    funcs[i] = function(x) {            // and store them in funcs
        console.log("My value: " + x); // each should log its value.
    }.bind(null, i);
}
for (var j = 0; j < 3; j++) {
    funcs[j]();                        // and now let's run each one to see
}

This way, each function will have it's own variable x and we set this x to the value of i in each iteration.

This is only one of the multiple ways to solve this problem.

Nae
25#
Nae Reply to 2017-12-26 20:27:59Z

With new features of ES6 block level scoping is managed:

var funcs = [];
for (let i = 0; i < 3; i++) {          // let's create 3 functions
    funcs[i] = function() {            // and store them in funcs
        console.log("My value: " + i); // each should log its value.
    };
}
for (let j = 0; j < 3; j++) {
    funcs[j]();                        // and now let's run each one to see
}

The code in OP's question is replaced with let instead of var.

Nae
26#
Nae Reply to 2017-12-26 22:46:04Z

Let's take advantage of new Function. Thus i stops to be a variable of a closure and becomes just a part of the text:

var funcs = [];
for (var i = 0; i < 3; i++) {
    var functionBody = 'console.log("My value: ' + i + '");';
    funcs[i] = new Function(functionBody);
}

for (var j = 0; j < 3; j++) {
    funcs[j]();
}
Costa
27#
Costa Reply to 2017-02-15 04:09:52Z

JavaScript functions "close over" the scope they have access to upon declaration, and retain access to that scope even as variables in that scope change.

var funcs = []

for (var i = 0; i < 3; i += 1) {
  funcs[i] = function () {
    console.log(i)
  }
}

for (var k = 0; k < 3; k += 1) {
  funcs[k]()
}

Each function in the array above closes over the global scope (global, simply because that happens to be the scope they're declared in).

Later those functions are invoked logging the most current value of i in the global scope. That's the magic, and frustration, of closure.

"JavaScript Functions close over the scope they are declared in, and retain access to that scope even as variable values inside of that scope change."

Using let instead of var solves this by creating a new scope each time the for loop runs, creating a separated scope for each function to close over. Various other techniques do the same thing with extra functions.

var funcs = []

for (let i = 0; i < 3; i += 1) {
  funcs[i] = function () {
    console.log(i)
  }
}

for (var k = 0; k < 3; k += 1) {
  funcs[k]()
}

(let makes variables that are block scoped instead of function scoped. Blocks are denoted by curly braces, but in the case of the for loop the initialization variable, i in our case, is considered to be declared in the braces.)

Nae
28#
Nae Reply to 2017-12-27 00:06:45Z

Use closure structure, this would reduce your extra for loop. You can do it in a single for loop:

var funcs = [];
for (var i = 0; i < 3; i++) {     
  (funcs[i] = function() {         
    console.log("My value: " + i); 
  })(i);
}
Nae
29#
Nae Reply to 2017-12-26 21:21:57Z

Many solutions seem correct but they don't mention it's called Currying which is a functional programming design pattern for situations like here. 3-10 times faster than bind depending on the browser.

var funcs = [];
for (var i = 0; i < 3; i++) {      // let's create 3 functions
  funcs[i] = curryShowValue(i);
}
for (var j = 0; j < 3; j++) {
  funcs[j]();                      // and now let's run each one to see
}

function curryShowValue(i) {
  return function showValue() {
    console.log("My value: " + i);
  }
}

See the performance gain in different browsers.

Nae
30#
Nae Reply to 2017-12-27 00:01:42Z

COUNTER BEING A PRIMITIVE

Let's define callback functions as follows:

// ****************************
// COUNTER BEING A PRIMITIVE
// ****************************
function test1() {
    for (var i=0; i<2; i++) {
        setTimeout(function() {
            console.log(i);
        });
    }
}
test1();
// 2
// 2

After timeout completes it will print 2 for both. This is because the callback function accesses the value based on the lexical scope, where it was function was defined.

To pass and preserve the value while callback was defined, we can create a closure, to preserve the value before the callback is invoked. This can be done as follows:

function test2() {
    function sendRequest(i) {
        setTimeout(function() {
            console.log(i);
        });
    }

    for (var i = 0; i < 2; i++) {
        sendRequest(i);
    }
}
test2();
// 1
// 2

Now what's special about this is "The primitives are passed by value and copied. Thus when the closure is defined, they keep the value from the previous loop."

COUNTER BEING AN OBJECT

Since closures have access to parent function variables via reference, this approach would differ from that for primitives.

// ****************************
// COUNTER BEING AN OBJECT
// ****************************
function test3() {
    var index = { i: 0 };
    for (index.i=0; index.i<2; index.i++) {
        setTimeout(function() {
            console.log('test3: ' + index.i);
        });
    }
}
test3();
// 2
// 2

So, even if a closure is created for the variable being passed as an object, the value of the loop index will not be preserved. This is to show that the values of an object are not copied whereas they are accessed via reference.

function test4() {
    var index = { i: 0 };
    function sendRequest(index, i) {
        setTimeout(function() {
            console.log('index: ' + index);
            console.log('i: ' + i);
            console.log(index[i]);
        });
    }

    for (index.i=0; index.i<2; index.i++) {
        sendRequest(index, index.i);
    }
}
test4();
// index: { i: 2}
// 0
// undefined

// index: { i: 2}
// 1
// undefined
neatsu
31#
neatsu Reply to 2017-10-13 08:58:39Z

Already many valid answers to this question. Not many using a functional approach though. Here is an alternative solution using the forEach method, which works well with callbacks and closures:

let arr = [1,2,3];

let myFunc = (val, index) => { console.log('val: '+val+'\nindex: '+index); };

arr.forEach(myFunc);

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